Question

To produce copper disulfide, how many grams of copper reacts with 10g of sulphur

Answer 1

Answer:

Explanation:

The idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then convert these masses to a mole ratio.

So, assuming that sulfur is in excess, you know that all the number of moles of copper that reacted will now be a part of the copper sulfide.

This mens that the difference between the recorded mass of the sulfide and the mass of the copper will be the mass of the sulfur.

m

copper sulfide

=

m

sulfur

+

m

copper

m

sulfur

=

1.880 g

−

1.500 g

=

0.380 g S

So, the mass of copper sulfide contains

1.500 g

of copper

0.380 g

of sulfur