Question

to proove tan 3A-tan 2A - tanA = tan 3A tan 2A tan A.​

Answer 1

Answer:

Tan(3a) = tan(2a+a) [as 3a =2a+a]

Applying the formula,

Tan(A+B)= tanA+tanB/1-tanAtanB

We get ,

Tan(3a)=Tan2a+Tan a / 1-Tan2aTan a

=>tan3a( 1-Tan2aTana) =Tan 2a + Tan a [ cross multiplication]

We get ,

Tan3a- Tan 3aTan2aTan a = Tan2a+ Tana

Now ,

Tan3a-Tan2a-Tan a = Tan 3a Tan2aTan a.

Is the required answer.

Step-by-step explanation:

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