To prove: CosA.sinA=1/tanA+cotA
Answers
Answered by
1
first solving RHS we get
=1/sinA/cosA+cosA/sinA
by taking LCM
=1/sin^2A+cos^2A/sinAcosA
As we know sin^2A+cos^2A=1 so by putting the value
=1/1/sinA.cosA
by rearranging we got
sinA.cosA
Hence RHS=LHS
Similar questions