Question

to prove
F=1/2 L×√tention/√ π×√r^2× density​

Answer 1

Answer :

44

Solution :

f∝(T/μ)1/2Lf∝(T/μ)1/2L

When μ = massperunit ≤n> h= ρa =ρ(πr2)μ=massperunit≤n>h=ρa=ρ(πr2)

So , f∝(T/ρ)1/2rLf∝(T/ρ)1/2rL

f2f1=(T2T1)1/2(ρ1ρ2)1/2(r1L1r2L2)f2f1=(T2T1)1/2(ρ1ρ2)1/2(r1L1r2L2)

=(12–√)(2–√)(4)=4