To prove Force= mass×acceleration
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Answered by
1
=> f directly lroportional to mv - mu / t
=> f d.p m(v-u) / t
=> f = k{ m(v-u)/t}
=> f = m(v-u) / t { k =1 }
=> f = ma ( a = v-u/t)♤
=> f = ma
PROVED.
=> f d.p m(v-u) / t
=> f = k{ m(v-u)/t}
=> f = m(v-u) / t { k =1 }
=> f = ma ( a = v-u/t)♤
=> f = ma
PROVED.
Answered by
0
as we know that
F is directly proprtional to dP/dt where P=momentum
let
F=kdP/dt
where k is any constant
as P=mv
F=kd(mv)/dt
F=kmdv/dt
as dv/dt=a
F=kma
experimentally k=1
therefore
F=ma
hope this helps
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