Question

To prove LAOC≈ BOD and LBOC ≈LAOD A B LAOC+ LAOD = 180° C--) + LBOD = 180º C Angles in lineas Pair) = C : LAOC + LAOD=2A8D+ LBOD ... From Ganda LAOC F... Similarly can prove LBOCE we​

Answer 1

Answer:

Angle AOC = 158

Angle BOC = 22

Angle AOD = 22

Angle BOD = 158

Step-by-step explanation:

Given that,

Angle AOC+ Angle BOC+ Angle BOD=338°

We know that

Sum of all angles is 360

Angle AOC+ Angle BOC+ Angle BOD + Angle AOD = 360

338 + angle AOD = 360 ( Acc. to Question)

Angle AOD = 360-338 =22

Angle AOD = angle BOC (Because they are vertically opposite angles)

They are equal to 22

And

Angle BOC + angle BOD = 180 ( Because linear pair...sum of those angles will be 180)

22+angle BOD = 180

Angle BOD = 180-22

Angle BOD = 158

Angle BOD = Angle AOC = 158 (Because vertically opposite angles are equal)

Angle AOC = 158

Angle BOC = 22

Angle AOD = 22

Angle BOD = 158

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