To prove :- sin (x+30) = cos x + sin(x-30)
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Step-by-step explanation:
A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the centre; equivalently it is the curve traced out by a point that moves in a plane so that its distance from a given point is constant.
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to prove the following is true
( sin x)( sin [ x +30°]) + (cos x)( sin[ x +120°]) = √3/2
replace sin [ x + 120°] with cos [ x + 30°]
since sin [x + 30° + 90°[= cos [ x + 30°]
gives us this equation to prove
(sin x)( sin [ x +30°]) + ( cos x)( cos [x + 30°]) = √3/2
replace x + 30° with -[ x + 30°]
cos [ x + 30°] = cos -[ x + 30°], cosine is an even function
sin [ x + 30°] = - sin -[x + 30°], sine is an odd function
Making the above substitutions, this is the equation we must prove
(cos)( cos -[x +30°]) - ( sin x)( sin -[x + 30]) = √3/2
Note
(cos)( cos -[x +30°]) - ( sin x)( sin -[x + 30]) = cos ( x-[x+30] = cos -30°
cos -30° = cos 30°
and
cos 30° = √3/2
so we have proved the equation
( sin x)( sin [ x +30°]) + (cos x)( sin[ x +120°]) = √3/2
( sin x)( sin [ x +30°]) + (cos x)( sin[ x +120°]) = √3/2
replace sin [ x + 120°] with cos [ x + 30°]
since sin [x + 30° + 90°[= cos [ x + 30°]
gives us this equation to prove
(sin x)( sin [ x +30°]) + ( cos x)( cos [x + 30°]) = √3/2
replace x + 30° with -[ x + 30°]
cos [ x + 30°] = cos -[ x + 30°], cosine is an even function
sin [ x + 30°] = - sin -[x + 30°], sine is an odd function
Making the above substitutions, this is the equation we must prove
(cos)( cos -[x +30°]) - ( sin x)( sin -[x + 30]) = √3/2
Note
(cos)( cos -[x +30°]) - ( sin x)( sin -[x + 30]) = cos ( x-[x+30] = cos -30°
cos -30° = cos 30°
and
cos 30° = √3/2
so we have proved the equation
( sin x)( sin [ x +30°]) + (cos x)( sin[ x +120°]) = √3/2
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