Question

To prove Sum of (m+n)th term of AP is two times of mth term​

Answer 1

Answer:

Step-by-step explanation:

Thge general nth term of an AP is a + (n -1)d.

 

From the given conditions,

 

m (a + (m-1)d) = n( a + (n-1)d)

=> am + m2d - md = an + n2d - nd

=> a(m-n) + (m+n)(m-n)d - (m-n)d = 0

=> (m-n) ( a + (m+n-1)d ) = 0

 

Rejecting the non-trivial case of m=n, we assume that m and n are different.

=> ( a + (m + n - 1)d ) = 0

 

The LHS of this equation denotes the (m+n)th term of the AP, which is Zero.

Answer 2

Answer:

it is prove that m +n term of AP is_