Question

To prove that   √2   is an irrational no.​

Answer 1

Answer:

To prove that the square root of 2 is irrational is to first assume that its negation is true. ... So, 2 = a b \sqrt 2 = {\Large{{a \over b}}} 2 =ba where a and b are integers but b ≠ 0 b \ne 0 b=0.

Answer 2

Step-by-step explanation:

To prove that the square root of 2 is irrational is to first assume that its negation is true. Therefore, we assume that the opposite is true, that is, the square root of 2 is rational. ... If 2 is a rational number, then we can express it as a ratio of two integers.

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