Question

To prove that area of two triangle with same height and common base are in proportion of 1:1 prove

Answer 1

Solution

To prove:-

• area of two triangle with same height and common base are in proportion of 1:1

Proof :-

Let,

∆ABC be first right triangle ,

Where,

• AB = H
• BC = B

Again,

Let, ∆PQR be second right triangle

Where,

• PQ = H'
• QR = B'

According to question,

• H = H'
• B = B'

Using Formula

$\boxed{\tt{\red{\:Area_{right\: triangle}\:=\:\dfrac{1\times Height\times Base}{2}}}}$

For First Right triangle

==> Area of first right triangle = (1 × H × B)/2

For second Right triangle

==> Area of second right triangle = (1 × H' × B')/2

Now, take ratio thier area's

= ( Area of first right triangle)/(Area of second right triangle)

keep Value

= [ (1 × H × B)/2] / [ (1 × H' × B')/2]

Here,

• H = H'
• B = B'

= [ (1 × H × B)/2] / [ (1 × H × B)/2]

= 1/1

Or,

= 1 : 1

That's Proved.

_____________________

Answer 2

Answer:

the answer is 1:1

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