Question

To prove that(i) sec (70° - θ) = cosec (20° + θ)

Answer 1

Answer:

look,

as we know,

secQ=cosec(90-Q)

As in the question,

L. H. S

sec(70-Q)=

cosec(90-(70-Q))

=cosec(90-70+Q)

=cosec(20+Q)=R. H. S

hence, proved....

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