Question

to prove that multiplication of integers is commutative 10 pairs

Answer 1

We have to give 10 pairs to show that the multiplication of integers is commutative.

For any integers say 'a' and 'b', the commutative property of multiplication states that

$a \times b = b \times a$

1. Consider 3 and 5

So, $3 \times 5 = 5 \times 3 = 15$

2. Consider 4 and -5

$4 \times -5 = -5 \times 4 = -20$

3. Consider -7 and -4

$-7 \times -4 = -4 \times -7 = 28$

4. Consider 9 and 6

$9 \times 6 = 6 \times 9 = 54$

5. Consider-4 and 9

$-4 \times 9 = 9 \times -4 = -36$

6. Consider -3 and -4

$-3 \times -4 = -4 \times -3 = 12$

7. Consider 8 and 9

$8 \times 9 = 9 \times 8 = 72$

8. Consider -5 and 5

$-5 \times 5 = 5 \times -5 = 25$

9. Consider 7 and 5

$7 \times 5 = 5 \times 7 = 35$

10. Consider -14 and -42

$-14 \times -42 = -42 \times -14 = 588$

Hence, integers  holds commutative property of multiplication.

Answer 2

Answer:

588

Step-by-step explanation:

-14×-42=-42×-14=58