To prove that objects of different weights fall at the same rate, Galileo dropped two objects with different weights from the Leaning Tower of Pisa in Italy. The objects hit the ground at the same time. When an object is dropped from a tall building, it falls about 16 ft in the first second, 48 ft in the second second, and 80 feet in the third second, regardless of its weight. How many feet would an object fall in the twelfth second?
Answers
Answer:
I am talking about fact that Galileo tried to prove that different objects falls at same rate. It won't go well since there is air resistance. Just tease on it.... Anyway, so to apply arithmetic sequence here, we have first term as 16, second term, and 80 as third term. 48-16 = 32 and 80-48=32 So we can see that common difference is 32. So you have a_t = -16+32t, where t is second.
Given: Galileo dropped two objects with different weights from the leaning tower of Pisa in Italy.
The object hit the ground at the same time.
an object is dropped from a tall about 16 ft in the first second, 48ft in the 2nd second, and 80 feet in the third second regardless of its weight.
To Find : How may feet would an object fall in the twelfth second?
Solution:
S = ut + (1/2)at²
u = 0 as dropped
Hence S = (1/2)at²
16 ft in the first second,
=> 16 = (1/2)a1²
=> a = 32
S = 16t²
S₁ = 16 * 1² = 16 ft
S in 2nd second = S₂ - S₁ = 16(2)² - 16(1)² = 48 ft
S in 3rd second = S₃ - S₂ = = 16(3)² - 16(2)² = 80 ft
So S in 12th second = S₁₂ - S₁₁ = 16(12)² - 16(11)² = 16 * 23
= 368 ft
Learn More:
the body started falling freely from the point above the ground it's ...
brainly.in/question/17279526
A ball dropped from 9th floor of a multistoried building reaches the ...
brainly.in/question/6233355