to prove that square root 2 +square root 3 is irrational
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Step-by-step explanation:
Assume that sqr2 + sqr3 = rational (in the form of a/b ; b not equal to 0)
square both sides;
2+3+2sqr6=a^2/b^2
2sqr6=(a^2/b^2)-5
2sqr6=(a^2-5b^2)/b^2
sqr6= (a^2-5b^2)/2b^2
this says that LHS is rational bcoz RHS is rational
But it contradicts the fact that sqr6 is irrational. therefore our assumption is wrong.
hence, sqr2+sqr3 is irrational.
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