to prove that the sum of all angle formed on the same side of a line at a point is 180
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Heya,
In ∆ABC,
Here line l | | m
We take AB as transversal line and get
1 = BAC ----- ( 1 ) ( Alternate interior angles )
And
Take AC as transversal line and get
2 = BCA ----- ( 2 ) ( Alternate interior angles )
And,
BAC + ABC + BCA = 180
(Sum of all internal angles of triangle is 180 )
Substitute values from equation 1 and 2 and get
ABC + 1 + 2 = 180
So, We can say Sum of these angle is a straight line ( l ) HENCE PROVED!
HOPE IT HELPS:-))
In ∆ABC,
Here line l | | m
We take AB as transversal line and get
1 = BAC ----- ( 1 ) ( Alternate interior angles )
And
Take AC as transversal line and get
2 = BCA ----- ( 2 ) ( Alternate interior angles )
And,
BAC + ABC + BCA = 180
(Sum of all internal angles of triangle is 180 )
Substitute values from equation 1 and 2 and get
ABC + 1 + 2 = 180
So, We can say Sum of these angle is a straight line ( l ) HENCE PROVED!
HOPE IT HELPS:-))
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