to prove x³-y³=(x-y)(x²+xy+y²)
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Step-by-step explanation:
(X-Y)³ = X³-Y³-3XY(X-Y)
keeping x³ and y³ on one side move remaining value on R.H.S to other side
Now,
X³-Y³= (X-Y)³+3XY (X-Y)
take (X-Y) as common out from RHS
X³-Y³ = (X-Y) ((X-Y)²+3XY)
Expand (X-Y)²
X³-Y³= (X-Y) ((X²+Y²-2XY+3XY)
X³-Y³= (X-Y)(X²+Y²+XY)
thus proved.
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