Question

to push open a door a person apply a force of 75 Newton acts on the handle the door at a angle of 600 from the normal to its plane if the handle is located at a distance 80 cm from the hand to talk appliance by him​

Answer 1

F=75,teta =30(because angle is from normal. We should calculate it from horizontal, therefore 30 degrees), r=80cm=0.8m

Torque =r×fsin teta therefore substituting we get, 75×0.8×sin30. 75×0.8×0.5=30