Question

To reach your school at 10:30 AM, if you start at 10 AM, first move 800 m to east, then 600 m to north and finally 200m to west, your average velocity and average speed are (in m/s)​

Answer 1

Answer:

Explanation:

To calculate speed

10 to 10:30 = 3o minutes= 30*60= 1800

Distance=800+600+200= 1600m

A. Speed= 1600/1800= 16/18 = 8/9

Now, option 1 has 8/9 as the average speed

therefore answer is  1 option

Hope this helps!

Bye

Answer 2

Concept:

The velocity is a vector quantity having magnitude as well as the direction whereas the speed is a scalar quantity having only the magnitude.

Given:

The path of the scholar, going to school, and time taken.

Find:

The average velocity and average speed (in m/s)​.

Solution:

Let, the direction of the west be -i, east be i, north be j, and south be -j,

So, the displacement will be

X= 800i + 600j - 200 i = 600i+ 600j

The time taken is 30 minutes, i.e, 1800 seconds.

Average velocity can be defined as total displacement in total time,

v = X/t = (600i+ 600j)/ 1800 = 1/3 (i+j) m/s

Total distance traveled,

s = 800 + 600 + 200 = 1600 m

The time taken is 30 minutes, i.e, 1800 seconds.

Average speed can be defined as total distance in total time,

v = s/t = 1600/1800 = 8/9 m/s

Hence, the average velocity is  1/3 (i+j) m/s and the average speed are 8/9 m/s. Hence, the correct option is (a) 1/3 (i+j) , 8/9.

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