Question

To reduce de Broglie wavelength of an electron from 10⁻¹⁰ m to 0.5 X 10⁻¹⁰ m, its energy should be (A) increased to 4 times
(B) doubled(C) halved
(D) decreased to fourth part

Answer 1

(B) doubled is the correct answer.

De-Broglie wavelength of the electron is the same as that of the 50 KeV X-ray photon.

1 eV and 2.5 eV respectively are based on the photon that is emitted at constant rate.

With successively illuminates the metal of work function 0.5 eV to high excellence.

Answer 2

Holla ^_^

☸ Required Answer is ⬇⬇ ⬇⬇ ⬇


⭕ B). doubled


Vielen Dank ♥