Question

To show
~> tan 48°tan 23° tan 42° tan 67° =1
please let me know the solution as soon as possible​

Answer 1

Answer:

here is urgent answer

Step-by-step explanation:

tan48°tan23°tan42°tan67°=1

cot(90-48)cot(90-23)tan42°tan67°=1

cot42°cot67°tan42°tan67°=1

cot42 tan 42 cot67 tan 67 =1

1=1

rhs =lhs

hence proved

Answer 2

$\huge\bf{Solution:-}$

$tan48° tan23° tan42° tan67° = 1 \\ </p><p>LHS = tan48° tan23° tan42° tan67° \\</p><p> = tan(90° - 42°) tan23° tan42° tan(90° - 23°)\\</p><p> = cot42° tan23° tan42° cot23° \\</p><p> = cot42° tan42° tan23° cot23° \\</p><p> = cot42° × \frac{1}{cot42°} tan23° × \frac{1}{tan23°}\\</p><p> = 1 × 1 \\</p><p> = 1 \\</p><p>hence RHS = LHS$