Math, asked by harshkamble0123, 7 months ago

to show that√2 is irrational number​

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Answered by Anonymous
3

Step-by-step explanation:

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Because √2 is not an integer (2 is not a perfect square), √2 must therefore be irrational. This proof can be generalized to show that any square root of any natural number that is not the square of a natural number is irrational.

{ { \boxed{ \underline{ \overline{ \overline{ \boxed{ \underline{ \mathrm \red{How  \: do \:  you \:  prove \:  something \:  is  \: irrational?}}}}}}}}}

If the number x solves some polynomial in the form of integers by positive powers of x, where the first term is a simple power of x, then x is either integer or irrational. So something like x²-n = 0 means that every sqrt(n) is irrational or integral.

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HOPE MY ANSWER HELPS

Answered by sc751
1

Step-by-step explanation:

it is true ans i think it may help you

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