Question

To show that the ratio of square of time period of a pendulum to its effective length is constant. Hence

find the value of acceleration due to gravity​

Answer 1

Answer:

The time period of simple pendulum can be written as

T=2π

g

l

l= length of pendulum

g= acceleration due to gravity at the position of simple pendulum.

Now when g is unchanged and as 2π is constant, T will only depend on length as the square root of it. So our given statement is true.

Explanation:

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