Question

To show that the ratio of square of time period of a pendulum to its effective length is constant. Hence

find the value of acceleration due to gravityl​

Answer 1

Answer:

The time period of simple pendulum can be written as 

T=2πgl

l= length of pendulum 

g= acceleration due to gravity at the position of simple pendulum.

Now when g is unchanged and as 2π is constant, T will only depend on length as the square root of it. So our given statement is true.

Explanation:

the acceleration due to gravity (g) is given by = GM/r2.

the value of g = 9.8 m/s^2