to solve by determinant method find D
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x+y=3........eq1
3x-2y-4=0
therefore 3x-2y=4........eq2
multiplying eq1 by 2 in both the side,
2x+2y=6.......eq3
adding eq3 from eq2,
3x-2y=4
2x+2y=6
5x=10
x=10÷5=2
x=2
3x-2y-4=0
therefore 3x-2y=4........eq2
multiplying eq1 by 2 in both the side,
2x+2y=6.......eq3
adding eq3 from eq2,
3x-2y=4
2x+2y=6
5x=10
x=10÷5=2
x=2
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