Math, asked by khushichordia672, 11 months ago

to solve it by equation reducible

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Answered by aryan1234243

0

Answer:

b²x-a2y+ab+ab=0

bx-ay+2ab=0

b²x-a²y+2ab=0

bx-ay+2ab=0

2ab will cancelled u get

b²x-a²y+bx-ay

bx(b+1)-ay(a+1)=0

a=-1 and b=-1 bx-ay=0

put the value here u get urs answer perfectly

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