Math, asked by ketki82, 1 month ago

To solve simultaneous equations 2x + y - 4 and 6x + 3y = 12

graphically, following are the ordered pairs.


2x + y = 4

x -1 0 2

y 6 4 0

(x, y) (-1, 6) (0, 4) (2, 0)



6x + 3y = 12

x -2 1 3

y 8 2 -2

(x, y) (-2, 8) (1, 2) (3, -2)


Observe the graph drawn and find the answer to the questions.

(1) Are the graphs of both the equations different or same?

(2) What are the relations between the coefficients of x, coefficients of y

and constant terms in both the equations?


(3) What conclusion can you draw when two equations are given but the

graph is only one line?​

Answers

Answered by kayamramya2005
17

Step-by-step explanation:

a1/a2=b1=b2=c1/c2

are concidence lines

(1/3=1/3=1/3)

1. different

2. a1/a2=b1=b2=c1/c2

3. no its concidencelines ( interesting lines)

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