Question

To solve the equation simultaneously equalize the coefficient of y:
7x+5y=19; 4x+3y=11,​

Answer 1

Step-by-step explanation:

Given

7x + 5y = 19

4x + 3y ,= 11

equalise y so y coefficients need to be cancelled

(7x + 5y = 19)*3

21x + 15y = 57

similarly ,

(4x + 3y = 11)*5

20x + 15y = 55

subtracting the equations

21x + 15y = 57

20x +15y = 55

we get x = 2 as y gets cancelled

if x = 2 then y =

4(2) +3y = 11

8 + 3y = 11

3y = 11-8

3y = 3

y = 1

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