Math, asked by priyanshu947725, 11 months ago

to
Solve the following equations.
(i) 3t-11 = 7
(iii) 5m - 3 = 3m+
(ii) 2y-5= (-3)
(v) 0,3x - 0.75 = 1.2x -0.12
(iv) 2x - 7 = 3x - 11
(vi) 0.18(y - 1) = 0.24 (2-3)
(vii) 7m-3(m - 2) = 2 (3
(viii) 0.01(t-0.2) + 0.09 -0.08 = 0
-5)
(ix) --2x - (x-1) + 8 =0 2m -
-= 3 + 2m
9
.
(1) 2K-3(k-1) + 5-0
(xii)
3m 3
1-2m * =0
8
(xiii)
*-3_5
X-5
olu
* (xiv) 25–5
3
5+2
2​

Answers

Answered by Misba786
3

1. 3t=7+11

3t=18

t=18÷3

t=6

3. 5m - 3m = 3

2m = 3

m = 3÷2

m = 3.2

2. 2y=-3+5

2y=-2

y=-2÷2

y=-1

4. 2x-3x=7-11

-1x=-4

x=-4÷-1

x=-1

I can this much....

Sorry..

Answered by rajendrabopche72
2

Answer:

sorry this que is so much ok

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