to solve the following linear equation by determinant method x + y= 3 ,3x -2y -4 =0
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x+y=3
x=3-y
3(3-y)-2y-4=0
9-3y-2y-4=0
9-5y-4=0
5-5y =0
-5y=0-5
-5y=-5
y= 5/5
y= 1
the answer is 1
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