Question

To solve the sum-write in the box. I am rectangle My breadth is x cm. My perimeter is 40 cm. My length is 3 times of my breadth Solution-Perimeter of rectangle is 40 cm. :: 2(x+ x) = 40 x= . 2x0x = 40, 8 x = 40, :. X= = , .. length of rectangle is and bread is 2([ - cm.​

Answer 1

Answer:

Step-by-step explanation:

$\neq x^{2} \leq \int\limits^a_b {x} \, dx \sqrt[n]{x} \alpha x^{2} \left \{ {{y=2} \atop {x=2}} \right. \\ \\ \\ \\ x^{2} x^{2} x^{2} \geq$

Answer 2

Answer:

Length is 5 cm, breadth is 15 cm

Step-by-step explanation:

The problem might be about finding the length and breadth of the rectangle

Given that  perimeter of rectangle = 40 cm

breadth of rectangle = x cm

given that length is 3 times of the breadth

let y be the length of the rectangle  

then length y = 3x

from given data perimeter of rectangle 2( y+x) = 40

                                                             ⇒ 2( 3x+ x) =40

                                                             ⇒   (3x + x) = 20      

                                                             ⇒   3x+ x = 20

                                                              ⇒  4x = 20

                                                             ⇒ x = 20/4 = 5 cm    

breadth x = 5 cm ⇒length  y = 3x =3(5) =15 cm