To solve X + Y = 3 ; 3X - 2Y - 4 = 0 , by determinant method find D .
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x+y=3 let the equation 1 × 3
3x-2y-4=0 after switch the 4 to another side then -4 converted into +4
so our 2 equation is 3x-2y=4
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• • let the equation 1 × with 3
we get 3x+3y=9
then subtract eq 1 from eq 2
3x+3y=9-----1
3x-2y=4------2
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we cut 3x
y=5
then the value of y put in eq 1
3x+3y=9
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•. • 3x+3(5)=9
3x+15=9
3x=9-15
3x= -6
x= -6/ 3
the value of x=-2
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