Question

to solve =x+y=3, 3x-2y-4=0 by determinant method find D​

Answer 1

Answer:

x = 2, y = 1

Step-by-step explanation:

x + y = 3..........(1)

3x - 2y - 4 = 0..........(2)

Rearrange (2)

3x - 2y = 4..........(3)

Multiply (1) by 2

2 × x + 2 × y = 2 × 3

2x + 2y = 6..........(4)

Add (3) and (4)

2x + 2y = 6

+ 3x - 2y = 4

_____________

5x = 10

x = 10 ÷ 5

x = 2

Substitute x in (1)

x + y = 3

2 + y = 3

y = 3 - 2

y = 1

So,

x = 2

y = 1