Question

to solve x+y=3 3x-2y-4=0 by determinant method find d

Answer 1

Answer:

Determinant method (Cramer’s Rule) :

In Cramer’s method, the equations are written as a1x + b1y = c1 & a2x + b2y = c2.

The value of determinant :

D = |a1 b1|

      |a2 b2|

D = a1b2 - a2b1

SOLUTION :

Option C is Correct : -5

GIVEN :

x + y = 3 , 3x - 2y - 4=0

Write the equations as a1x + b1y = c1 & a2x + b2y = c2.

x + y = 3 , 3x - 2y = 4

Here, a1= 1,b1= 1,c1= 3

a2 = 3, b²= - 2 , c2 = 4

The value of determinant :

D = |a1 b1|

      |a2 b2|

D = |1 1 |

      |3 -2|

D = a1b2 - a2b1

D = (1×-2) - ( 3×1)

D = -2 -3 = -5

Hence , the value of D is - 5.

HOPE THIS WILL HELP YOU…

Step-by-step explanation:

Answer 2

Answer:

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