Question

To solve x + y = 3 ; 3x - 2y -4 = 0 by determinant method find D. *​

Answer 1

Step-by-step explanation:

D is not in the question then how can we find?

Answer 2

$x + y = 3$

$3x - 2y - 4 = 0$

$3x - 2y = 4$

$d = | \frac{1}{3} \frac{1}{ - 2} |$

$= 1 \times - 2 - 1 \times 3$

$= - 2 - 3$

$= - 5$

D=-5