to solve x + y = 3; 3x – 2y – 4 = 0 by determinant method,find Dx
(A) 5 (B) 10 (C) -5 (D) -10
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x+y=3 ___i ×2
3x-2y=4___ii ×1
by equation ---i
x=3-y______ iii
determined eq.iii in ii
3(3-y)-2y=4
9-3y-2y=4
-5y= -5
so, y=1.
then, the value of y determined eq. 1
x+y=3
x+1=3
x=2.
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