Question

To solvex=y+3;3x - 2y - 4 = 0 by
determinant method find Dx.​

Answer 1

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow x= y+3$

$\sf\dashrightarrow equation, 3x-2y-4=0$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow \text{ VALUE OF x}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore 3x-2y-4=0$

$\sf\implies 3(y+3)-2y-4=0$

$\sf\implies 3y+9-2y-4=0$

$\sf\implies 3y-2y+9-4=0$

$\sf\implies y+5=0$

$\sf\implies y=-5$

$\large{\boxed{\bf{ \star\:\: y= -5\:\: \star}}}$

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Answer 2

${\tt{\purple{\underline{\underline{\huge{Answer:}}}}}}$

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow x= y+3$

$\sf\dashrightarrow equation, 3x-2y-4=0$

$\large\bold{TO\:FIND,}$

$\sf\dashrightarrow \text{ VALUE OF x}$

$\large\bold{SOLUTION,}$

$\sf\therefore 3x-2y-4=0$

$\sf\implies 3(y+3)-2y-4=0$

$\sf\implies 3y+9-2y-4=0$

$\sf\implies 3y-2y+9-4=0$

$\sf\implies y+5=0$

$\sf\implies y=-5$

$\large{\boxed{\bf{ \:\: y= -5\:\: }}}$

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