Question

To stretch a spring 0.02 m, work done is 0.4 J. Calculate spring constant.

Answer 1

Answer:

Potential Energy/Work done=

$\frac{1}{2} k {x}^{2}$

So

$0.4 = \frac{1}{2} \times k \times {0.02}^{2} \\ or \: k = \frac{0.4 \times 2}{( {0.02})^{2} } = 2000 \:$

Thus, spring constant=2000 N/m