Question

to study image distance corresponding to an object placed at 2f , 3f, 4f distance in front of a convex lens







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Answer 1

• Using Lens Formula , (1/f)=(1/v)−(1/u)
• put f=f , u=−f/2
• we get v=−f
• As v is negative , the image is in the same side as of object so image is virtual because we have used a convex lens.

• magnification m=(−v/u)=−2 so the image will be double of the object in the size.

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Answer 2

Answer:

☆Using Lens Formula , (1/f)=(1/v)−(1/u)

☆put f=f , u=−f/2

☆we get v=−f

☆As v is negative , the image is in the same side as of object so image is virtual because we have used a convex lens.

☆magnification m=(−v/u)=−2 so the image will be double of the object in the size.

Hope it helps!

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