Question

/* To take two numbers as input then count number of evens present within those two
numbers where display will be done in main() method
Using following method prototype:
int evenCount() */
(user Defined method)​

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

The given co‎‎de is written in Java.

import java.util.*;

public class CountEven{

   static int evenCount(int a,int b){

       int count=0,d;

       for(;a!=0;a/=10){

           d=a%10;

           if(d%2==0)

               count++;

       }

       for(;b!=0;b/=10){

           d=b%10;

           if(d%2==0)

               count++;

       }

       return count;

   }

   

   public static void main(String args[]){

       Scanner _=new Scanner(System.in);

       System.out.print("Enter first number: ");

       int a=_.nextInt();

       System.out.print("Enter second number: ");

       int b=_.nextInt();

       _.close();

       System.out.printf("Number of even digits in %d and %d is %d.",a,b,evenCount(a,b));

   }

}

$\texttt{\textsf{\large{\underline{Explanation}:}}}$

• Here, I have assumed that we have to count the number of even digits. To do this, we will initialize count = 0 and divide the number repeatedly and get the last digit. If that digit is even, add 1 to count. At last, return count.

See the attachment for output.

Answer 2

Answer:

Program-

import java.util.*;

public class Main

{

int evenCount1(int a)

{

int r=0,c=0;

while(a!=0)

{

r=a%10;

if(r%2==0)

c++;

a=a/10;

}

return c;

}

int evenCount2(int b)

{

int t=0,e=0;

while(b!=0)

{

t=b%10;

if(t%2==0)

e++;

b=b/10;

}

return e;

}

public static void main(String args[])

{

Scanner in=new Scanner(System.in);

Main ob=new Main();

int a1,b1;

System.out.println("Enter the numbers");

a1=in.nextInt();

b1=in.nextInt();

System.out.println("The numbers of even digits in "+a1+"="+ob.evenCount1(a1));

System.out.println("The numbers of even digits in "+b1+"="+ob.evenCount2(b1));

}

}

Note:-

• I didn't wrote using 1 function evenCount as you can only return only 1 function.
• In order to calculate even numbers within both the numbers you need to create 2 methods.

Output is attched.