Question

to tell the angle opposite to the equal side an isosceles triangle are equal​

Answer 1

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⬇️HERE IS YOUR ANSWER⬇️

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Take a triangle ABC, in which AB=AC.

Construct A bisector of angle A meeting BC at P


In AABP and AACP

AP=AP[common] AB=AC[given] angle BAP=angle CAP[by construction]

Therefore, AABP congruent AACP[S.A.S]

This implies, angle ABP=angle ACP[C.P.C.T]

Hence proved that angles opposite to equal sides of a triangle are equal

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