To the adjacent figure Ab parallel cd-find the value of x,y andz
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angle CPQ = angle PQR = 80° ( because CD parellel to AB and alternate interior angles are equal)
so , 80° + 2x + 3x = 180° [ straight angle]
5x = 180° - 100°
5x = 80°
x = 80/5 = 16°
Now , angle DPR = angle PRQ [ 3x = y] ( because CD parellel to AB and alternate interior angles are equal)
3(16) = y
y = 48°
Now, y° + z° = 180° [ linear pair]
48° + z° = 180°
z° = 180° - 48°
z° = 132°
Therefore , x = 16° , y = 48° , z = 132°
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