Question

+ to the circle with
10 In the given figure, FG is a tangent to the cir
centre A. If angle DCB = 15°and CE = DE. then
angle GCE and angle BCE.
CBSE 2015.​

Answer 1

Answer:

GCE=60°

BCE=15°

Step-by-step explanation:

ang. FCD=90°.

(angle between diameter and tangent is 90°)

therefore ang.GCD= 90°

ang.DCB=ang.BCE=15°

(therefore-CE=DE)

ang.GCD=DCB+BCE+GCE

90°=15°+15°+GCE

90°-30°=GCE

HENCE-GCE=60°

HOPE IT HELPS YOU!!!

Answer 2

Answer:

ang BCE=30

ang.ECG=45

Step-by-step explanation:

by fig. we can say that triangle CDE is a right isoceles triangle

so, ang.DCE=45

and though , ang. BCE=45-15

                      ang. BCE=30

by the property of tangent

ang. DCG=90

so, angECG=90-45

     ang.ECG=45