Question

To the driver of a car A moving with velocity
TA =(31 -4ſ)m/s, a second car B appears to have a
velocity (51 + 129 m/s. The true velocity of the car B is​

Answer 1

Given : To the driver of a car A moving with velocity VA = (3i - 4j) m/s

a second car B appears to have a  velocity (5i + 12j) m/s.

To Find : The true velocity of the car B is​

Solution:

Velocity of Car A  VA= (3i - 4j) m/s

Assume that True Velocity of Car B = VB  m/s

To the driver of a car A , car B appears to have a  velocity = VB - VA

To the driver of a car A , car B appears to have a  velocity =  (5i + 12j) m/s.

=> VB - VA = (5i + 12j) m/s

=> VB = VA + (5i + 12j) m/s

VA= (3i - 4j) m/s

=> VB = (3i - 4j) + (5i + 12j) m/s

=> VB  = (8i + 8j) m/s

The true velocity of the car B is​ (8i + 8j) m/s

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