Question

To the driver of a car A moving with velocity VA = (31 - 4ſ)m/s, a second car B appears to have a velocity (5i +12j) m/s. The true velocity of the car Bis
(21 +167)m/s
(81 +8ſ) m/s
(-2-16) m/s
(+81 +8)) m/s​

Answer 1

Answer:

The correct answer is Option (d) (+81 +8)) m/s​

Explanation:

Given: To the driver of a car A travelling at VA = (3i - 4j) m/s,

A second car B appears to be travelling at a speed of (5i + 12j) m/s.

To Find: Here it is asking to find the true velocity of the car B is

Calculation:

Velocity of Car A  VA= (3i - 4j) m/s

So, we need to Assume that the True Velocity of Car B will be = VB  m/s

To the driver of a car A , car B appears to have a  velocity = VB - VA

To the driver of a car A , car B appears to have a  velocity =  (5i + 12j) m/s.

=> VB - VA = (5i + 12j) m/s

=> VB = VA + (5i + 12j) m/s

VA= (3i - 4j) m/s

=> VB = (3i - 4j) + (5i + 12j) m/s

=> VB  = (8i + 8j) m/s

Therefore, The true velocity of the car B is​ (8i + 8j) m/s

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