to the driver of a car A moving with velocity va=(3i^-4j^)m/s a second car B appears to have a velocity (5i^+12j^)m/s . The true velocity of tje car B is.
Answers
Given : To the driver of a car A moving with velocity VA = (3i - 4j) m/s
a second car B appears to have a velocity (5i + 12j) m/s.
To Find : The true velocity of the car B is
Solution:
Velocity of Car A VA= (3i - 4j) m/s
Assume that True Velocity of Car B = VB m/s
To the driver of a car A , car B appears to have a velocity = VB - VA
To the driver of a car A , car B appears to have a velocity = (5i + 12j) m/s.
=> VB - VA = (5i + 12j) m/s
=> VB = VA + (5i + 12j) m/s
VA= (3i - 4j) m/s
=> VB = (3i - 4j) + (5i + 12j) m/s
=> VB = (8i + 8j) m/s
The true velocity of the car B is (8i + 8j) m/s
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