Chemistry, asked by mmsravanisravs, 1 year ago

To the galvanic cell Fe(s)/Fe2+(0.05M)//Ag+(0.001M)/Ag(s) calculate the emf of the cell (E0Fe2+/Fe=-0.44V , E0 Ag+/Ag = 0.80V)

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Answered by harivirat09082004

0

Answer:

question purila bro sorry

Explanation:

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