To the given figure AB and CD are two parallel chords of a circle with centre O and diamtre 10 cm such that AB=6cm and CD=8cm. If OP parallel to AB and OQ parallel to CD determine the length of PQ
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Given OP⊥AB and OQ⊥CD
CQ = QD = 3 cm
AP = BP = 4cm
In △OPA
OP
2
=OA
2
–AP
2
=r
2
–4
2
=25–16=9
⟹OP=3
In △OCQ
OQ
2
=
r
2
–3
2
=4
PQ=OP+OQ=4+3=7cm
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