English, asked by kamlkarbhoir, 11 months ago

To throw me, you’d prefer a crowd. What am I?

Answers

Answered by poojan
9

Party it is!

Explanation :

  • To throw a party, we need crowd. Celebration it is, isn't it?  Like, who wants to celebrate alone?

  • These type of puzzles are known as riddles.

  • To solve a riddle, all you need to do is, just to decrypt the given message.

  • Decrypting the message will be easier when you start to understand the riddle part by part. If you go with a complete sentence right from the base, it may confuse you.

Learn more :

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2) Scratch my head, see me turn from black to red. What am I?

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Answered by Anonymous
0

Explanation:

Question:-

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer:-

The length of Rectangle is 36 m

The breadth of rectangle is 28 m

The area of Given rectangle is 1008 m².

To find:-

Length and breadth of rectangle

Area of rectangle

Solution:-

Let the breadth be x

Length = 8 + x

Perimeter = 128 m

\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}

According to question,

\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}

\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:

\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}

\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}

\large{ \tt: \implies \: \: \: \: \: 2x = 56}

\large{ \tt: \implies \: \: \: \: \: x = 28}

The breadth of rectangle is 28 m

Length = 8 + x = 28 + 8 = 36 m

\large{ \boxed{ \mathfrak{area = l \times b}}}

\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}

\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }

The area of Given rectangle is 1008 m².

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