Question

to to my love of life.....
with with which I can can spend my entire life....
and will never get bored even after spending thousands of hours with you.

MY LOVE :-CHEMISTRY

calculate q, W, ∆H and ∆U for a process in which 88 gram of nitrous oxide gas N2O school from 165 degree Celsius to 55 degree Celsius at a constant pressure of 5 ATM.

[ if Cv= 30.5 j/k mol and
R= 8.3 j/ mol-k]

​

Answer 1

Answer:

Cv = 30.38 J/(K∙Mol), and Cp = 38.70 J/(K∙Mol).

The molar mass of N2O is: 44.013 g/mol.  Hence 94.0 g of N2O is 2.136 Mole of N2O.

q = -38.70*2.136*(161-57) = -8.60 (kJ)

w = -P*ΔV = -nRΔT = 2.136*8.314*(161-57) = 1.85 (kJ)

ΔE = q+w = -8.60+1.85 = -6.75 (kJ)

ΔH = ΔE + PΔV = ΔE -w = q = -8.60 (kJ)

Happy to help :)