Question

To Two forces of 4N acts on body
at an angle of 60 find magnitude
and direction of the resultant force
acting
the body. please solve step by step quickly​

Answer 1

Answer:

The resultant of two forces acting at an angle of 60∘ is R1=√49 R 1 = 49 .

Answer 2

Answer

Howdy!!

your answer is ---

Given, two force act on a body at angle 60° , exact force is equal to 4 N

so, magnitude of resultant force is --

\begin{gathered}\sqrt{ {4}^{2} + {4}^{2} + 2 \times 4 \times 4 \cos(60) } \\ = \sqrt{16 + 16 + 32 \times \frac{1}{2} } \\ = \sqrt{32 + 16} \\ = \sqrt{48} = 4 \sqrt{3} newton\end{gathered}

4

2

+4

2

+2×4×4cos(60)

=

16+16+32×

2

1

=

32+16

=

48

=4

3

newton